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cab5d03ab7
regex metacharacters ({}[]()^$.|*+? and \) now have to be escaped using
'\' if they should be used as literals.
3 lines
63 B
Plaintext
3 lines
63 B
Plaintext
1 ""
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5 !="0\.000000" !="0\.990000" !="1\.000000" !="2\.000000"
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